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0.05x^2-6x+74.8=0
a = 0.05; b = -6; c = +74.8;
Δ = b2-4ac
Δ = -62-4·0.05·74.8
Δ = 21.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{21.04}}{2*0.05}=\frac{6-\sqrt{21.04}}{0.1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{21.04}}{2*0.05}=\frac{6+\sqrt{21.04}}{0.1} $
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